Find the perimeter of the rectangle whose width is 46 cm and the length is 1 dm longer.

Let’s find what the length of this rectangle is equal to.

According to the condition of the problem, the width of this rectangle is 46 cm, and the length of this rectangle is 1 dm greater than its width.

Since there are 10 centimeters in one decimeter, the length of this rectangle is 10 cm greater than its width, which means that the length of this rectangle is:

46 + 10 = 56 cm.

Find the perimeter P of a given rectangle as the doubled sum of the length and width of this rectangle:

P = 2 * (56 + 46) = 2 * 102 = 204 cm.

Answer: the perimeter of this rectangle is 204 cm.