Find the perimeter of the triangle ABC if A (3; 5) B (0; 1) C (3; 0).

1. To find the perimeter of a triangle, you need to find the length of each side

Applying the theory of Pythagoras, we find the lengths of the sides

2. | AB | = √ (0 – 3) ² + (1 – 5) ² = √9 + 16 = √25 = 5

| AC | = √ (3 – 3) ² + (0 – 5) ² = √0 + 25 = √25 = 5

| BC | = √ (3 – 0) ² + (0 – 1) ² = √9 + 1 = √10

3.P = AB + AC + BC = 5 + 5 + √10 = 10 + √10

Answer: 10 + √10