Find the perimeter of triangle ABC if AB = 2/15 meters, BC is 4 times more than AB, and AC is 1/15 meter less than BC.

Let’s find the length of the side BC of the given triangle ABC.

According to the condition of the problem, the length of the side AB of this triangle is 2/15 meters, and the side BC is 4 times larger than the side AB, therefore, the length of the side BC is:

| Sun | = | AB | * 4 = (2/15) * 4 = 8/15 m.

Find the length of the side AC of this triangle ABC.

According to the condition of the problem, the AC side is 1/15 meter less than the BC side, therefore, the AC side length is:

| AU | = | Sun | – 1/15 = 8/15 – 1/15 = 7/15 m.

Find the perimeter of triangle ABC:

| AB | + | Sun | + | AC | = 2/15 + 8/15 + 7/15 = 17/15 m.

Answer: The perimeter of triangle ABC is 17/15 m.