Find the perimeter of triangle ABC, where the length of the AB side is 9 cm, the length of the AC side is 80%

Find the perimeter of triangle ABC, where the length of the AB side is 9 cm, the length of the AC side is 80%, and the length of the CB side is 60% of the length of the AB side.

1) Knowing the size of the side AB and the fact that the size of the side of the AC is 80% of the length AB, we calculate the length of the AC. To do this, we find 80% of 9 cm: 9: 100 · 80 = 7.2 (cm);

2) Knowing the size of the side AB and the fact that the size of the side CB is 60% of the length AB, we calculate the length of the CB. To do this, we find 60% of 9 cm: 9: 100 · 60 = 5.4 (cm);

3) Having determined the size of all sides of the triangle ABC, you can calculate the perimeter of this figure: P = AB + BC + CB = 9 + 7.2 + 5.4 = 21.6 (cm).

Answer: The perimeter of the triangle is 21.6 cm.



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