Find the point of intersection of the graphs of linear functions: y = x-2 and y = 3-2x

In order to find the point of intersection of the graphs of the linear functions y = x – 2 and y = 3 – 2x, you need to equate their right sides and solve the equation for the variable x.
We get:
x – 2 = 3 – 2x (the expression with the variable x is transferred from the right side of the equation to the left, changing the sign to the opposite);
x + 2x – 2 = 3;
x + 2x = 3 + 2;
x + 2x = 5;
x * (1 + 2) = 5;
x * 3 = 5 (in order to find an unknown factor, you need to divide the product by a known factor);
x = 5: 3;
x = 5/3;
x = 1 2/3;
y = 1 2/3 – 2 = 1 2/3 – 1 3/3 = – 1/3.
The point of intersection of the graphs of linear functions y = x – 2 and y = 3 – 2x has coordinates (1 2/3; -1/3).
Answer: (1 2/3; -1/3).