Find the potential energy of a body with a mass of 500 g thrown vertically upward at a speed of 10 m / s

Find the potential energy of a body with a mass of 500 g thrown vertically upward at a speed of 10 m / s at the highest point of ascent.

g = 9.8 m / s2.

V = 10 m / s.

Ep -?

1 way.

The potential energy of the body En is determined by the formula: En = m * g * h.

The maximum lifting height h is expressed by the formula: h = V ^ 2/2 * g.

En = m * g * V ^ 2/2 * g = m * V ^ 2/2.

Ep = 0.5 kg * (10 m / s) ^ 2/2 = 25 J.

Method 2.

The total mechanical energy at the moment of throwing the body E consists only of the kinetic energy Ek: E = Ek.

The total mechanical energy E at the highest point of the trajectory consists only of the potential energy En: E = En.

According to the conservation law, the total mechanical energy remains unchanged.

Ek = En.

Ek = m * V ^ 2/2.

En = m * V ^ 2/2.

Ep = 0.5 kg * (10 m / s) ^ 2/2 = 25 J.

Answer: the potential energy of the body at the highest point of ascent is En = 25 J.