Find the pressure exerted by a body weighing 300g on the floor if the support area is 200mm2.

The pressure of a body on the surface of the floor in this case is the ratio of the force with which this body presses on the floor to the area of support of the body itself.
P = F / S, where F = m * g (m is the body mass (m = 300 g = 0.3 kg), g is the acceleration of gravity (we take g equal to 9.8 m / s ^ 2)), S – support area (200 mm ^ 2 = 0.0002 m ^ 2).
Hence: P = (m * g) / S = (0.3 * 9.8) / 0.0002 = 14700 Pa = 14.7 kPa
Check: Pa = (kg * m / s ^ 2) / m ^ 2 = kg / (m * s ^ 2) = Pa.
Answer. The body pressure on the floor surface is 14.7 kPa.