Find the pressure of 0.89 g of hydrogen in a volume of 500 cm ^ 3 at a temperature of 17 degrees.

Let’s start by converting all units of measurement from the SI system.

We convert the temperature to Kelvin:

T = 273 + 17 = 290 K.

From cm ^ 3, we translate the value of the volume into m ^ 3:

V = 500 cm ^ 3 = 500 * (10 ^ -2) ^ 3 m ^ 3 = 500 * 10 ^ -6 m ^ 3.

We translate grams into kg:

m = 0.89 g = 0.89 * 10 ^ -3 kg.

To calculate, we also need the value μ = 0.002 kg / mol for diatomic hydrogen.

Let’s apply the Mendeleev-Cliperon equation:

PV = vRT;

PV = mRT / μ;

P = mRT / μV;

P = (0.89 * 10 ^ -3 * 8.31 * 290) / (0.002 * 500 * 10 ^ -6) = 2 144 811 Pa.