Find the pressure of a leg and 2 legs that is applied to the ground by a person with

| June 2, 2021 | education

Find the pressure of a leg and 2 legs that is applied to the ground by a person with an area of 1 leg 0.02065 square meters. and weighing 40.5 kg

Given:

m = 40.5 kilograms – the mass of a person;

g = 10 m / s2 – free fall acceleration;

S = 0.02065 square meters – the area of ​​one person’s night.

It is required to determine the pressure P (Pascal) that a person produces, standing on one leg and on two legs.

Let’s find the force of gravity acting on a person:

G = m * g = 40.5 * 10 = 405 Newton.

Then the pressure on one leg will be equal to:

P = G / S = 405 / 0.02065 = 19612.6 Pascal = 19.6 kPa.

The pressure of a person on two legs will be equal to:

P1 = G / (2 * S) = 405 / (2 * 0.02065) = 405 / 0.0413 = 9806.3 Pascal = 9.8 kPa.

Answer: the pressure of a person standing on one leg is 19.6 kPa, on two legs – 9.8 kPa.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.