Find the probability that when throwing 2 dice, the total of the points drawn will be less than 10.

Since a dice has 6 faces, there are 6 chances for a single toss of this dice.

Therefore, when rolling two dice, there are a total of 6 * 6 = 36 points to drop.

Let us list all the cases when the sum of the dropped points will be greater than or equal to 10 when tossing up two playing points:

4, 6;
5, 5;
6, 4.

Therefore, in 3 cases out of 36, the sum of the dropped out points will be greater than or equal to 10 and the probability of such an event is 3/36 = 1/12.

Then the probability that the sum of the dropped out points will be less than 10 is 1 – 1/12 = 11/12.

Answer: The probability of such an event is 11/12.