# Find the projection of the force F acting on a body weighing 500 kg if the body moves

May 27, 2021 | education

| **Find the projection of the force F acting on a body weighing 500 kg if the body moves in a straight line and its displacement equation is S = 10t + t ^ 2**

Given:

m = 500 kilograms is the mass of a moving body;

S (t) = 10 * t + t ^ 2 – the equation of body motion.

It is required to determine F (Newton) – the projection of the force acting on the body.

Let’s find the equation of the body’s velocity:

v (t) = S (t) ‘= (10 * t + t ^ 2)’ = 10 + 2 * t.

Let’s find the equation of body acceleration:

a (t) = v (t) ‘= (10 + 2 * t)’ = 2.

It can be seen that the acceleration is constant and equal to 2 m / s ^ 2. Then:

F = m * a = 500 * 2 = 1000 Newtons.

Answer: the projection of the force acting on the body is 1000 Newtons.

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