Find the projection of the force F acting on a body weighing 500 kg if the body moves
May 27, 2021 | education
| Find the projection of the force F acting on a body weighing 500 kg if the body moves in a straight line and its displacement equation is S = 10t + t ^ 2
Given:
m = 500 kilograms is the mass of a moving body;
S (t) = 10 * t + t ^ 2 – the equation of body motion.
It is required to determine F (Newton) – the projection of the force acting on the body.
Let’s find the equation of the body’s velocity:
v (t) = S (t) ‘= (10 * t + t ^ 2)’ = 10 + 2 * t.
Let’s find the equation of body acceleration:
a (t) = v (t) ‘= (10 + 2 * t)’ = 2.
It can be seen that the acceleration is constant and equal to 2 m / s ^ 2. Then:
F = m * a = 500 * 2 = 1000 Newtons.
Answer: the projection of the force acting on the body is 1000 Newtons.
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