Find the radius of the circle around triangle ABC. if it is known that side AB = 3, angle ACB = 30 degrees.

A corollary from the theorem of sines states that the ratio of the side of a triangle to the sine of the opposite angle is a constant value for a given triangle and is equal to two radii of the circumscribed circle. The angle ACB is opposite to the side AB, then R = AB / 2sinACB = 3/2 * 0.5 = 3/1 = 1.



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