Find the radius of the circle circumscribed around the triangle ABC, if BC = 12 √2 cm, angle A = 45 degrees.
| May 15, 2021 | education
The inscribed angle BAC = 450 and rests on the arc BC, then the degree honey of the arc BC = 2 * 45 = 90. Then the central angle BOC = 90, and the triangle BOC is rectangular.
OB ^ 2 + OS ^ 2 = BC ^ 2.
2 * OB ^ 2 = 2 * R ^ 2 = 144 * 2.
R ^ 2 = 144.
R = 12 cm.
Answer: The radius of the circumscribed circle is 12 cm.
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