Find the radius of the circumscribed circle of the triangle ABC if AC = 3cm and the angle B = 30 degrees.

To solve this problem, let’s use the sine formula:
a / sin A = b / sin B = c / sin C = 2R.
Opposite corner B lies side b, therefore b / sin B = 2R. Plug in the numbers and solve the equation.
Sine 30 is 1/2 or 0.5.
3 / (1/2) = 2x
3 * 2 = 2x
6 = 2x
-2x = -6
x = -2 / -6
x = 3.
Answer: the radius of the circumscribed circle of the triangle is 3.