Find the range of a body thrown horizontally at a speed of 72 km / h from a height of 80 m.

The flight time will be determined by the vertical travel time. Let’s write down the law of motion:

x = h – gt ^ 2/2, g – gravitational acceleration, t – time.

We take the ground level as the reference point, then x = 0:

h – gt ^ 2/2 = 0;

t ^ 2 = 2h / g;

t = √2h / g.

We substitute the known values:

t = √2 * 80/10 = 4 s.

During this time, the body will fly in the horizontal direction (72 km / h = 20 m / s):

20 * 4 = 80 m.

Answer: the desired flight range of the body is 80 m.



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