Find the ratio AC: BC sides of triangle ABC, angle A 120 degrees, angle B 30 degrees
| September 20, 2021 | education
By the AC sine theorem: sin B = BC: sin A;
AC: BC = sin B: sin A;
sin A = sin 120 ° ≈ 0.866; sin B = sin 30 ° = 0.5;
AC: BC = 0.5: 0.866 = 1: 1.73.
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