Find the sharp corners of a right triangle if one is 60 degrees larger than the other.

A right-angled triangle is a triangle with one of its angles equal to 90 °.

Since the sum of all the angles of the triangle is 180º, one of the angles is 60º greater than the other, then:

x is the degree measure of the angle ∠A;

x + 60 – degree measure ∠В;

90º is the degree measure of the angle ∠С;

180º is the sum of all the angles of the triangle;

x + x + 60 + 90 = 180;

x + x = 180 – 90 – 60;

2x = 30;

x = 30/2 = 15;

∠А = 15º;

∠В = 15 + 60 = 75º.

Answer: the acute angles of the triangle are equal to ∠A = 15º; ∠В = 75º.