Find the side of the BCDE rhombus if its diagonals are 12 cm and 16 cm.

univerkov | May 27, 2021 | education

The diagonals of the rhombus are perpendicular and are halved at point O. BО = ВD / 2 = 12/2 = 6 cm, СО = CE / 2 = 16/2 = 8 cm.

In a right-angled triangle BCO, according to the Pythagorean theorem, BC ^ 2 = BO ^ 2 + CO ^ 2 = 36 + 64 = 100.

BC = 10 cm.

Answer: The side of the rhombus is 10 cm.

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