Find the side of the sun of the triangle sd, if it is known that sd = the root of 2, the angle at = 30 degrees, and the angle d = 45 degrees.

Let us draw the height of CH Therefore, the angle BNS = 90 AND the angle BHD = 90 Consider the triangle CHD CHD = 90 CDH = 45 DCH = 180-90-45 = 45 Triangle CHD equilateral CD ^ 2 = CH ^ 2 + DH ^ 2 2 = 2CH CH = DH = 1 Consider a triangle BCH Angle SVN = 30 => BC = 2 by the property of a right-angled triangle. (The side opposite to the 30 degree angle is half the hypotenuse)
Answer: 2