Find the sides and angles of an isosceles triangle if the angle at its base is 75 degrees
Find the sides and angles of an isosceles triangle if the angle at its base is 75 degrees, the perimeter is 46 cm and its base is 8 cm larger than the side.
The angles at the base are equal, which means that the angle at the top will be:
180 ° – (75 ° + 75 °) = 30 °.
We introduce the variable x and denote the length of the lateral side of this triangle, then the length of the base is (x + 8) cm.Let’s use the formula for the perimeter of a triangle and compose the equation:
x + x + x + 8 = 46
3x = 38
x = 38/3 = 12 2/3 (cm) – side;
12 2/3 + 8 = 20 2/3 (cm) – base.
The sides turned out not quite “pretty”. Possibly a typo and a 47 cm perimeter, then the equation would be:
3x = 39
x = 13 (cm) – side;
13 + 8 = 21 (cm) – base.
Answer: the angles of the triangle are 75 °, 75 °, 30 °, sides are 12 2/3 cm, 12 2/3 cm, 20 2/3 cm.