Find the sides and area of triangle ABC, if A (3; 4), B (-3; 4) and C (-3; -4).

Modulus of vector AB ^ 2 = (- 3-3) ^ 2 + (4-4) ^ 2 = 36
AB = 6
Vector modulus BC ^ 2 = (- 3 + 3) ^ 2 + (- 4-4) ^ 2 = 64
BC = 8
Modulus of vector AC ^ 2 = (- 3-3) ^ 2 + (- 4-4) ^ 2 = 100
AC = 10
Find the area of a triangle using Heron’s formula: S ^ 2 = p (p-a) (p-b) (p-c), where p is the half-sum of the sides, and a, b, c are the sides of the triangle
p = (6 + 8 + 10) / 2 = 12
S ^ 2 = 12 (12-6) (12-8) (12-10) = 12 * 6 * 4 * 2 = 576
S = 24
Answer: S = 24, a = 6, b = 8, c = 10