Find the sides of a parallelogram, the perimeter of which is 72 cm, and one of the sides is 3 times smaller from the other.

1. The tops of the parallelogram – A, B, C, D. The perimeter (P) of the parallelogram = 72 cm. AB is 3 times less than AD.

2. AB is 3 times less than AD. Therefore, AD = 3AB.

3.Considering that the sides of the parallelogram opposite each other are equal, the perimeter of this geometric figure is calculated by the formula:

P = 2 (AB + AD) = 72 cm.

AB + AD = 36 cm. Substitute in this expression 3AB instead of AD:

AB + 3AB = 36 cm.

4AB = 36 cm.

AB = 9 cm.

AD = 3AB = 3 x 9 = 27 cm.

Answer: AB = CD = 9 cm, AD = BC = 27 cm.



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