Find the sides of an isosceles trapezoid, the bases of which are 14cm and 8cm, and one of the corners is 120 degrees.

Consider an isosceles trapezoid of AВСD. From the corners B and c, we lower the perpendiculars ВK and CM to the base of the blood pressure. A rectangle KВСM and two right-angled triangles AВK and MСD were formed. Consider a triangle ABK. The AKВ angle is straight and equal to 90 degrees. The AВK angle is 120 – 90 = 30 degrees. The side of Ak is equal to (14 – 8) / 2 = 3 centimeters. The leg of a right-angled triangle ABK lies against an angle of 30 degrees, which means that the hypotenuse AB is 2 * 3 = 6 centimeters.
Answer: The sides of the trapezoid are 6 centimeters long.