Find the sides of an isosceles triangle if the perimeter is 60 cm and the sides are 1: 2.

1. Vertices of the triangle – A, B, C. Perimeter (P) = 60 centimeters. AB: AC = 1: 2.

2. AB: AC = 1: 2 according to the problem statement. Therefore, AC = 2AB.

3. AB = BC, as sides of an isosceles triangle.

4. P = AB + BC + AC = 60 centimeters. We substitute AB instead of BC and 2AB instead of AC in this expression:

AB + AB + 2AB = 60 centimeters.

4AB = 60 centimeters.

AB = 60: 4 = 15 centimeters.

AC = 2AB = 2 x 15 = 30 centimeters.

BC = AB = 15 centimeters.

Answer: AB = BC = 15 centimeters, AC = 30 centimeters.



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