Find the sides of an isosceles triangle whose perimeter is 127 cm, and the side is 5 cm larger than the base.

let x (cm) be the length of the side of an isosceles triangle, then (x-5) (cm) is the length of the base of an isosceles triangle.
Using the perimeter formula, we find the sides of an isosceles triangle:
P = a + b + c;
127 = x + x + (x-5);
127 = 3x – 5;
3x = 132;
x = 44;
a = b = 44 (cm). Then c = 44 – 5 = 39 (cm).
Answer: 39; 44; 44.