Find the sides of the rectangle if their difference is 23 and the diagonal of the rectangle is 37.
March 25, 2021 | education
| To solve the problem, consider the figure.
By condition:
a – b = 23.
a = 23 + b.
AC = 37.
By the Pythagorean theorem, AC ^ 2 = a ^ 2 + b ^ 2.
37 ^ 2 = (23 + b) ^ 2 + b ^ 2.
1369 = 529 + 46 * b + 2 * b ^ 2.
2 * b ^ 2 + 46 * b – 840 = 0.
b ^ 2 + 23 * b – 420 = 0.
Let’s solve the quadratic equation.
D = b ^ 2 – 4 * a * c = 23 ^ 2 – 4 * 1 * (-420) = 529 + 1680 = 2209.
b1 = (-23 – √2209) / (2 * 1) = (-23 – 47) / 2 = -70 / 2 = -35. (does not match, since <0).
b2 = (-23 + √2209) / (2 * 1) = (-23 + 47) / 2 = 24/2 = 12.
Side b = 12 cm.
a = 23 + 12 = 32 cm.
Answer: The sides of the rectangle are 12 and 32 cm.
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