Find the sides of triangle A1B1C1 whose perimeter is 136, if the sides of a similar triangle ABC are known: AB = 12 BC = 14 AC = 8

Perimeter of triangle ABC: P = AB + BC + AC = 12 + 14 + 8 = 34 (cm);

P1 / P = 136/34 = 4;

Since the triangles are similar, the ratio of similar sides is equal to the ratio of their

perimeters, that is:

A1B1 / AB = B1C1 / BC = A1C1 / AC = 4;

A1B1 = AB * 4; A1B1 = 12 * 4 = 48 (cm);

B1C1 = BC * 4; B1C1 = 14 * 4 = 56 (cm);

A1C1 = AC * 4; A1C1 = 8 * 4 = 32 (cm).