Find the sine and cosine of acute angles A and B of a triangle with a right angle C if: BC = 21, AB = 29, AC = 20
| February 24, 2021 | education
The sine of an acute angle of a right triangle is the ratio of the length of the opposite leg to the length of the hypotenuse.
SinBAC = BC / AB = 21/29.
SinABC = AC / AB = 20/29.
The cosine of an acute angle of a right-angled triangle is the ratio of the length of the adjacent leg to the length of the hypotenuse.
CosBAC = AC / AB = 20/29.
CosABC = DC / AB = 21/29.
Answer: SinBAC = 21/29, CosBAC = 20/29, SinABC = 20/29, CosABC = 21/29.
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