Find the sine of the angle D of the triangle CDE, if it is known that DE = 15, CE = 18, the sine of the angle C = 1/6.

We know from the condition that a triangle CDE is given, and its known sides are DE = 15; CE = 18, and the sin of the angle C = 1/6 is also known.

We need to find the sin of the angle D of a given triangle.

To solve the problem, we will apply the sine theorem. Let’s remember her:

a / sin A = b / sin B = c / sin C.

The sides of a triangle are proportional to the sines of the opposite angles.

For a given triangle, we have:

DE / sin C = CE / sin D,

Let us express:

sin D = (sin C * CE) / DE.

It remains for us to substitute the values and calculate:

Sin D = 1/6 * 18/15 = 1/5.