Find the slope of the tangent to the graph of the functions f (x) = 0.5x ^ 2 + 1 at the point x0 = 3.
| September 1, 2021 | education
The slope of the tangent y = kx + b to the graph of the function is equal to the value of the derivative at the point of tangency.
k = f ‘(x0) = f’ (3)
First, let’s find the derivative:
f ‘(x) = (0.5x ^ 2 + 1)’ = 2 * 0.5 * x = x
f ‘(3) = 3. Thus, the coefficient of the tangent is 3.
Answer. 3.
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