Find the smaller angle of the parallelogram if its area is 40√3 cm, and the sides are 10 cm and 8 cm.

1. Let’s designate: parallelogram ABCD. Let us drop the height BN from the vertex B.

S = AD * BN;

BN = S: AD;

BN = 40√3: 10;

BN = 4√3.

2. Consider triangle ABN.

sin of angle NAB = BN: AB;

sin of angle NAB = 4√3: 8 = √3 / 2;

angle NAB = 60 °.

Answer: The smaller parallelogram is 60 °.



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