Find the smaller diagonal of a rhombus whose sides are 2 and the acute angle is 60 degrees.
| June 27, 2021 | education
Since the diagonals of the rhombus divide the angles at its apex in half, the angle OAB = BAD / 2 = 60/2 = 30. Then the leg OB lies opposite the angle 30, and then it is equal to half the length of the hypotenuse AB. ОВ = AB / 2 = 2/2 = 1 cm.
The diagonals of the rhombus, at the intersection point, are divided in half, then the diagonal BD = 2 * BO = 2 * 1 = 2 cm.
Answer: The smaller diagonal is 2 cm.
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