Find the specific heat capacity of cast iron if, when a cast iron part weighing 20 kg cools down from 130 degrees

Find the specific heat capacity of cast iron if, when a cast iron part weighing 20 kg cools down from 130 degrees Celsius to 80 degrees Celsius, 0.55 MJ of heat is released

Initial data: m (mass of the cooling cast-iron part) = 20 kg; t1 (initial temperature of the cast iron part) = 130 ºС; t2 (final temperature of the cast iron part) = 80 ºС; Q (released amount of heat) = 0.55 MJ (0.55 * 10 ^ 6 J).

We express the specific heat capacity of cast iron from the formula: Q = C * m * (t1 – t2), whence C = Q / (m * (t1 – t2)).

Let’s make the calculation: C = 0.55 * 10 ^ 6 / (20 * (130 – 80)) = 550 J / (kg * K).

Answer: According to the calculation, the specific heat capacity of cast iron is 550 J / (kg * K).