Find the speed of propagation of sound vibrations in air v, if the wavelength lambda = 340 mm,

| January 28, 2021 | education

Find the speed of propagation of sound vibrations in air v, if the wavelength lambda = 340 mm, and the vibration frequency v = 1000 Hz. What is the maximum vibrational velocity of the particles of the medium (dt / dy), if the amplitude of vibrations is A = 2.00 μm?

λ = 340 mm = 0.34 m.
v = 1000 Hz.
A = 2 μv = 2 * 10 ^ -6 m.
V -?
Vcol -?
The speed of propagation of a sound wave V in air is determined by the formula: V = λ
v, where λ is the length of the sound wave, v is the frequency of the sound wave.
V = 0.34 m * 1000 Hz = 340 m / s.
The vibrational velocity Vvol of air particles is determined by the formula: Vvol = A * w, where A is the amplitude of oscillations, w is the angular frequency of oscillations.
The angular frequency of vibrations w is determined by the formula: w = 2 * P * v, where P is the number pi, v is the frequency.
Vcol = A * 2 * P * v.
Vcol = 2 * 10 ^ -6 m * 2 * 3.14 * 1000 Hz = 12.56 * 10 ^ -3 m / s.
Answer: the speed of propagation of a sound wave in air is V = 340 m / s, the maximum vibrational speed of air particles is Vcol = 12.56 * 10 ^ -3 m / s.



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