Find the speed of the body at time t = 4c, if S = t ^ 3 + 2t-0/5 (m).

To find the value of the body’s velocity versus time from the function S = t + 2t², it is necessary to take the derivative (first-order derivative) from this function and substitute the time value into it:
S = t³ + 2t – 0/5.
S ‘= V = (t³ + 2t – 0/5)’ = 3t² + 2 – 0 = 3t² + 2.
Body speed at time t = 4 s:
V = 3t² + 2 = 3 * 4² + 2 = 3 * 16 = 50 m / s.
Answer: The speed of the body at time t = 4 s is 50 m / s.