Find the stiffness of the spring which, under the action of a force of 10n, lengthened by 10cm.
| August 10, 2021 | education
Initial data: F (force acting on the spring) = 10 N; Δl (spring elongation) = 10 cm.
SI system: Δl = 10 cm = 10/100 m = 0.1 m.
The spring rate can be determined from the formula (Hooke’s law): | F | = | Fupr | = k * Δl, whence k = F / Δl.
Let’s calculate: k = 10 / 0.1 = 100 N / m.
Answer: The spring rate is 100 N / m.
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