Find the sum and difference of the largest two-digit number that has 8 digits plus the smallest two-digit number.
| August 1, 2021 | education
The largest two-digit number whose sum of digits equals 8 is “80”, since 8 + 0 = 8. The smallest two-digit number is “10”. Find the sum of the numbers “80” and “10”: 80 + 10 = 90. Find the difference between the numbers “80” and “10”: 80 – 10 = 70.
Answer: 90; 70.
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