Find the sum of the first eighty terms of the sequence bn) given by b (n) = 2n-5
| August 22, 2021 | education
b1 = 2 * 1 – 5 = – 3.
b80 = 2 * 80 – 5 = 155.
S80 = (b1 + b80) * 80/2 = (- 3 + 155) * 80/2 = – 152 * 40 = – 6080.
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