Find the sum of the first five terms of the arithmetic progression if a1 = 5, d = 2

a1 = 5 is the first term of the arithmetic progression
d = 2 is the difference between the members of the progression
find the next members of the arithmetic progression, up to 5 members
the second term of the arithmetic progression is a2 = a1 + d = 5 + 2 = 7
the third term of the arithmetic progression is a3 = a 2 + d = 7 + 2 = 9
the fourth term of the arithmetic progression is a4 = a3 + d = 9 + 2 = 1 1
the fifth term of the arithmetic progression is a5 = a4 + d = 1 1 + 2 = 13
the sum of the progression is then = 5 + 7 + 9 + 11 + 12 = 12 + 20 + 12 = 44
answer: 44