Find the sum of the first twelve terms of the arithmetic progression, in which a1 = -5, d = 3.

Given:

a1 = -5

d = 3

n = 12

Find: S12.

Solution:

To find the sum of the arithmetic progression of the first 12 terms, we use the formula Sn = (2 * a1 + d (n – 1)) * n / 2.

S12 = (2 * (-5) + 3 (12 – 1)) * 12/2 = (-10 + 33) * 12/2 = 138.

Answer: S12 = 138.



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