Find the sum of two numbers if it is known that it is more than one of them by 15 and more than the other by 38.

Let us denote the sought numbers by A and B.

By the condition of the problem, it is known that the sum of these numbers S = A + B is more than one of them by 15.

Then we have:

S – A = (A + B) – A = B = 15

It is also known that the sum S of these numbers is 38 more than the other.

Hence,

S – B = (A + B) – B = A = 38.

We got that A = 38 and B = 15. Therefore, their sum S is equal to:

S = A + B = 38 + 15 = 53.

Answer: the sum of numbers is 53.