Find the surface area of a rectangular parallelepiped and its volume, if its width is 6 dm

| March 2, 2021 | education

Find the surface area of a rectangular parallelepiped and its volume, if its width is 6 dm, and it is 2 times less than its length, but 1 dm greater than its height.

To begin with, we find the length of a rectangular parallelepiped, if, according to the condition, it is 2 times the width, equal to 6 dm:

6 * 2 = 12 (dm).

Let’s find the height of the rectangular parallelepiped, if it is known that it is less than the width by 1 dm:

6 – 1 = 5 (dm).

1) Now we calculate the surface area of ​​a rectangular parallelepiped, which is equal to twice the sum of the areas of its three faces:

S = 2 (6 * 12 + 6 * 5 + 12 * 5) = 2 (72 + 30 + 60) = 2 * 162 = 324 (dm²).

2) Find the volume of a rectangular parallelepiped, which is equal to the product of the values ​​of its three dimensions:

V = 6 * 12 * 5 = 360 (dm³).

Answer: the surface area of ​​a rectangular parallelepiped is 324 dm², the volume is 360 dm³.



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