Find the surface area of a rectangular parallelepiped if its dimensions are 2 dm, 3 dm and 11 dm.

The parallelepiped has 6 faces in total
Two of which can be found as a * b, and another 4 of which a * c.
a = 2dm
b = 3dm
c = 11dm
We find two faces:
2 * (2dm * 3dm) = 12dm ^ 2
Find 4 faces:
4 * (3dm * 11dm) = 132dm ^ 2
We add:
132 + 12 = 144 (dm ^ 2)
Answer: 144 dm ^ 2



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