Find the surface area of a rectangular parallelepiped if its dimensions are 3.6 cm, 7.4 cm and 5.5 cm.

The surface area of a rectangular parallelepiped consists of two base areas (upper and lower), two side faces and two faces, one of which is front and the other is rear. Let us introduce the notation a = 3.6 cm; b = 7.4 cm; c = 5.5 cm.

S = 2 (S1 + S2 + S3);

S1 = ab; S2 = ac; S3 = bc.

S1 = 3.6 * 7.4 = 26.64 (cm ^ 2)

S2 = 3.6 * 5.5 = 19.8 (cm ^ 2)

S3 = 7.4 * 5.5 = 40.7 (cm ^ 2)

S = 2 (26.64 + 19.8 + 40.7) = 2 * 87.14 = 174.28 (cm ^ 2)

Answer. 174.28 cm ^ 2