Find the surface area of a rectangular parallelepiped if its length is 12.2, which is a fifth of its width

Find the surface area of a rectangular parallelepiped if its length is 12.2, which is a fifth of its width, and its height is 1.22 less than its length.

The length of the rectangular parallelepiped is known.

This value is one fifth of the width of the parallelepiped, and is 1.22 times greater than the height of the parallelepiped. Find the surface area of the parallelepiped.

Let a be the length of the figure, b the width, and c the height of the parallelepiped.

a = 12.2 cm.

a = b / 5;

b = 5 * a = 61 cm.

a = 1.22 * z;

z = a / 1.22 = 12.2 / 1.22 = 10 cm.

The sides of the parallelepiped are known. Find the surface area:

Sпов = 2 * (a * b + b * c + a * c);

Spov = 2 * (12.2 * 61 + 61 * 10 + 12.2 * 10);

Spov = 2 * (744.2 + 610 + 122);

Spov = 2952.4 cm².