Find the surface area of a rectangular parallelepiped that is 12 cm long, 7 cm shorter than the length, and 2 cm

Find the surface area of a rectangular parallelepiped that is 12 cm long, 7 cm shorter than the length, and 2 cm greater than the width. Find the sum of the lengths of all the edges of the parallelepiped.

Let’s designate the length as a = 12cm; the width is denoted by b = a – 7cm = 5cm; the height is denoted by c = b + 2cm = 7cm.
In a rectangular parallelepiped, all six faces are rectangles. Their areas are equal to the product of their sides.
Total surface area of all faces:
S = 2 * (S1 + S2 + S3) = 2 * (a * b + a * c + b * c) = 2 * (12 * 5 + 12 * 7 + 5 * 7) = 2 * 179 = 358cm ^ 2.
The rectangular parallelepiped has 12 ribs. Their total length is:
L = 4 * (a + b + c) = 4 * (12 + 5 + 5) = 96cm.