Find the surface area of a rectangular parallelepiped (that is, the sum of the areas of its edges)
Find the surface area of a rectangular parallelepiped (that is, the sum of the areas of its edges) if its changes are 5cm, 6cm and 3cm.
A rectangular parallelepiped has 6 faces, each of which is equal to the opposite face, that is, three pairs of identical faces.
Let’s say that the measurements of one of the faces are 5 cm and 6 cm, then its area is:
S = 5 * 6 = 30 cm².
Since the parallelepiped has one more same face, their total area will be 30 * 2 = 60 cm².
The area of a face with measurements of 5 cm and 3 cm will be equal to S = 5 * 3 = 15 cm², and of two such faces, respectively, 15 * 2 = 30 cm².
The area of a face with measurements of 6 cm and 3 cm will be equal to S = 6 * 3 = 18 cm ², and two such faces are 18 * 2 = 36 cm ².
Thus, the surface area of this rectangular parallelepiped will be equal to:
S = 60 + 30 + 36 = 126 cm².
Answer: 126 cm².