Find the surface area of a rectangular parallelepiped (that is, the sum of the areas of its edges)

Find the surface area of a rectangular parallelepiped (that is, the sum of the areas of its edges) if its changes are 5cm, 6cm and 3cm.

A rectangular parallelepiped has 6 faces, each of which is equal to the opposite face, that is, three pairs of identical faces.

Let’s say that the measurements of one of the faces are 5 cm and 6 cm, then its area is:

S = 5 * 6 = 30 cm².

Since the parallelepiped has one more same face, their total area will be 30 * 2 = 60 cm².

The area of ​​a face with measurements of 5 cm and 3 cm will be equal to S = 5 * 3 = 15 cm², and of two such faces, respectively, 15 * 2 = 30 cm².

The area of ​​a face with measurements of 6 cm and 3 cm will be equal to S = 6 * 3 = 18 cm ², and two such faces are 18 * 2 = 36 cm ².

Thus, the surface area of ​​this rectangular parallelepiped will be equal to:

S = 60 + 30 + 36 = 126 cm².

Answer: 126 cm².



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