Find the surface area of a rectangular parallelepiped, the length and width of which are 5cm each

| February 1, 2021 | education

Find the surface area of a rectangular parallelepiped, the length and width of which are 5cm each, and the height is 4cm. Find the sum of the lengths of all its edges.

Since the length of the parallelepiped is equal to its width, there is a 5 × 5 cm square at the base, and its upper base will be the same. The side faces of the rectangular parallelepiped are 5 × 4 cm in size, there are only 4 of them.

The area of ​​any rectangle can be found using the following formula:

S = ab, where a and b are the sides of the rectangle.

Let’s first find the area of ​​the base of the parallelogram:

Sb = 5 * 5 = 25 cm².

Now let’s find the area of ​​its side face:

Sb = 5 * 4 = 20 cm².

The total surface area of ​​a rectangular parallelepiped can be found as follows:

Spp = 2Sb + 4Sb.

Let’s find it:

Spp = 2 * 25 + 4 * 20 = 50 + 80 = 130 cm².

Any parallelepiped has only 12 faces. This parallelepiped has 8 faces equal to 5 cm, and 4 more faces – 4 cm each.Let’s find the sum of their lengths:

8 * 5 + 4 * 4 = 40 + 16 = 56 cm.

Answer: the surface area of ​​the rectangular parallelepiped is 130 cm², the sum of the lengths of all the edges of the rectangular parallelepiped is 56 cm.



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