Find the surface area of a rectangular parallelepiped whose dimensions are 9 M, 24 m, 11 m.
| March 18, 2021 | education
The surface area of a rectangular parallelepiped is equal to twice the sum of the areas of the three faces of this parallelepiped.
S = 2 (Sa + Sb + Sc) = 2 (ab + bc + ac)
a = 9 m
b = 24 m
c = 11 m
S = 2 (9 * 24 + 24 * 11 + 11 * 9) = 2 (216 + 264 + 99) = 2 * 579 = 1158 m ^ 2.
Answer: the surface area of a rectangular parallelepiped is 1158 m ^ 2
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