Find the surface area of a rectangular parallelepiped whose height is 24cm

Find the surface area of a rectangular parallelepiped whose height is 24cm, the width is 4 times less, and the length is equal to the difference in height and width

The area of a rectangular parallelepiped is equal to the sum of the areas of the three faces of the parallelepiped multiplied by two:

S = 2 • (ab + bc + ac).

By the condition of the problem, a = 24 cm; b – 4 times ‹a; c = a – b.

Find sides b and c:

b = 24: 4 = 6 (see)

c = 24 – 6 = 18 (see)

Now you can calculate the area of the parallelepiped:

S = 2 • (24 • 6 + 6 • 18 + 24 • 18) = 2 • (144 + 108 + 432) = 2 • 684 = 1368 (cm2.).

Answer: the area of a rectangular parallelepiped is 1368 cm2.